Construct APQR such that, mP = 80°, mQ = 70°, I(QR) = 5.7 cm.
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Step-by-step explanation:
In A PQR,
P+2Q+ ZR 180° (Angle
sum property)
80°+70°+ ZR = 180°
150+ ZR = 180°
ZR = 180° 150°
30
Steps of constructions:
(1) Draw seg QR of length 5.7
cm.
(2) Draw ray QA such that
RQA 70°.
(3) Draw ray RB such that
zQRB 30°.
(4) Name the point of
intersection of ray RB and QA
as P
Therefore, A PQR is the
required triangle.
THIS IS JUST AN EXAMPLE.
YOU CAN REFER THIS SUM AND DO THE SAME FOR YOUR QUESTION
Thank You!!
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