Question

Construct APQR such that PQ = 5.5 cm, QR = 7 cm and PR = 8.5 cm. Measure ​

Answer 1

(i) Draw a line segment PQ of length 6 cm.

(ii) With P as centre, draw an arc of radius 4.5 cm.

(iii) With Q as centre, draw an arc of radius 7 cm which intersects the previous arc at R.

(iv) Join PR and QR. Then ∆PQR is the required triangle.

Answer 2

Answer:

1. Draw a line segment QR of length 3cm.

2. Now, we draw 95° degrees from point Q.

3. Taking Q as centre, 5cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

4. Joint PR and label the sides.

Thus, PQR is the required triangle.

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