Question

Construct AXYZ in which YZ=4.1cm, 2Y=45, and XY+XZ 6.7 cm,
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Answer 1

Question :-

Construct a ΔXYZ in which YZ = 4.1 cm, ∠Y = 45° and (XY + YZ) = 6.7 cm.

$\begin {gathered} \end {gathered}$

Solution :-

Steps of Construction :-

1. Draw YZ = 4.1 cm
2. Construct ∠ZYP = 45°
3. Along YP, set off YQ = 6.7 cm
4. Join ZQ
5. Draw the Perpendicular Bisector of ZQ to intersect YQ at X
6. Join XZ

Then, ΔABC is the Required Triangle . . .

$\begin {gathered} \end {gathered}$

Verification :-

On measuring, we find that -

XY + YZ = (3.6 + 3.1) cm = $\bf 6.7 cm$

$\begin {gathered} \end {gathered}$

Additional Information :-

Angle :- Two Rays which Originate from the Same (Initial) Point forms an ANGLE.

The Rays are called the ARMS of the Angle and Initial Point is called the VERTEX of the Angle . . .

Answer 2

Answer:

The answer is 5439

Step-by-step explanation:

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