Construct AXYZ in which YZ=4.1cm, 2Y=45, and XY+XZ 6.7 cm,
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Steps of Construction :-
Draw YZ = 4.1 cm
Construct ∠ZYP = 45°
Along YP, set off YQ = 6.7 cm
Join ZQ
Draw the Perpendicular Bisector of ZQ to intersect YQ at X
Join XZ
Then, ΔABC is the Required Triangle . . .
Verification :-
On measuring, we find that -
XY + YZ = (3.6 + 3.1) cm = 6.7 cm
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