Construct DABC in which BC= 7cm, angleABC= 45°
and AB+AC=13cm
write steps of construction.
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2
Answer:
i) Draw BC=7cm
ii) Construct ∠YBC = 45°
iii) From Ray BY, cut off line segment BD=AB+AC=13cm
iv) Join CD
v) Draw the perpendicular bisector of CD meeting BY at A.
vi) Join AC to obtain the required triangle ABC.
Justification,
Since A lies on the perpendicular bisector of CD.
Therefore AC=AD
Now, BD = 13cm
=> BA+AD = 13cm
=> BA+AC = 13cm
Hence, ABC is the required triangle.
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
u can put 45° in the place of 75°
hope you understand
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