Question

Construct Def in which angle e=75 degrée with de=ef=7cm
Construct eg=9cm,the bisector of def

Answer 1

Step-by-step explanation:

Given,

Construction of in which \triangle EFD△EFD where DE=7\ cmDE=7 cm and \angle D=75\ degree∠D=75 degree

We know,

The construction of a triangle is not possible if sum of two sides is greater than third side of triangle.

(DE+EF) > DF(DE+EF)>DF

⇒DE > (DF-EF)DE>(DF−EF)

⇒ 7 > (DF-EF)7>(DF−EF)

We can take the value of (DF-EF)(DF−EF) is 6.5\ cm6.5 cm

Following steps:

Draw line segments DE=7\ cmDE=7 cm using scale.

At DD , draw an angle 75\ degree75 degree like \angle EDX=75\ degree∠EDX=75 degree

Cuts a point PP on line DXDX like DP=6.5\ cmDP=6.5 cm

Join PEPE

Bisect the line PEPE and the bisecting line cuts the DXDX at FF

Join EFEF

Hence, \triangle EFD△EFD is the required triangle