Construct DEF in which DE=5 cm EF 5 cm and DF=5cm. Write the steps of construction
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1. Draw a line segment which is sufficiently long using ruler.
2. Locate points D and E on it such that DE=5 cm
3. With D as centre and radius 5 cm draw an Arc
4. With E as centre and radius 5 cm draw another cutting the previous Arc at F.
5. join DF and EF.
- Then DEF is the required triangle
Answered by
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Answer:
- draw a line segment EF=5cm.
- with centre draw an Arc of 5 CM and with F centre draw another arc of 5 centimetre.
- the two arcs will intersect each other at a point name it as D.
- join DE & DF.
- therefore DEF is the required Triangle.
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