Question

Construct DEF in which DE=5cm,DF=3cm and m EDF=90​

Answer 1

Answer:

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Step-by-step explanation:

To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90o.

Steps of construction:

(a) Draw a line segment DF=3cm

(b) At point D an angle of 90o with the help of compass i.e., ∠XDF=90o.

(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E

(d) Join EF

It is the required right angle triangle DEF