Question

Construct ΔDEF such that DE=EF=6 cm, ∠F=45° and construct its circumcircle.

Answer 1

Answer:

ΔDEF is constructed

Step-by-step explanation:

DE=EF=6 cm

=> ∠F = ∠D = ∠45°

=> ∠E = 180° - 45° - 45° = 90°

Step 1 : Draw DE = 6cm using ruler

Step 2 draw angle of 90° at E using protector

Step 3 Draw EF = 6 cm

Step 4 Join DF

ΔDEF is constructed

Step 5 Draw perpendicular bisector of DE

Step 6 Draw perpendicular bisector of EF

Step 7 Locate intersection of Perpendicular bisector

Step 8 : use intersection point as center and using compass take radius upto any vertices and draw circle

circumcircle is constructed