Construct each of the following and give justification :
A triangle PQR given that QR = 3cm,∠ PQR = 15degree
∘
and QP - PR = 2cm.
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Answer:
I just know did the same sum but it has 45° angle. Here it is:
Steps of construction :
1. Draw a ray OX and cut off a line segment QR = 3cm.
2. At Q, construction ∠ YQR = 45° with the help of protractor .
3. On QY , cut off QS = 2cm.
4. Join RS.
5. Draw perpendicular bisector of RS to meet QY at P.
6. Join PR. Then PQR is the required triangle.
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