construct it on the notebook please
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steps of construction:-
1. draw a line segment BC of 6cm.
2.Consruct an angle of 45° on point B and C respectively.
3.mark the point A where these angles intersect.
(the triangle ABC with AB =BC and angle A=90° is formed.)
4.draw an acute angle from point B downwards and divide the arm in 5 units.
5. now join the point a5 to C
6 from point a4 draw a parallel line to intersect BC at C'
7.now from point C' draw a line parallel to AC to intersect AB at C'
the triangle A'BC' is the required triangle which has all the sides equal to 4/5 of the triangle ABC.
hope this will help you
mark it brainliest
©prashantrai
1. draw a line segment BC of 6cm.
2.Consruct an angle of 45° on point B and C respectively.
3.mark the point A where these angles intersect.
(the triangle ABC with AB =BC and angle A=90° is formed.)
4.draw an acute angle from point B downwards and divide the arm in 5 units.
5. now join the point a5 to C
6 from point a4 draw a parallel line to intersect BC at C'
7.now from point C' draw a line parallel to AC to intersect AB at C'
the triangle A'BC' is the required triangle which has all the sides equal to 4/5 of the triangle ABC.
hope this will help you
mark it brainliest
©prashantrai
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PrashantRai2810:
archi my answer is better and clear read and to understand
you should mark my answer as brainliest
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aarchi please mark my answer as a brainliest....
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please mark my answer as brainliest aarchi
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