Question

Construct it with construction steps

Answer 1

1) draw a line AB=4.9cm
2) with the same radius =4.9cm with A as center draw an arc to cut the line AB at B
3) with the same radius =4.9cm with B as center draw an arc to cut the large arc at say D'
4) with the same radius =4.9cm with D' as center draw an arc to cut the large arc at say C
5) join A to C and B to C to form ΔABC with ∠A=120° and AB=AC=4.9cm
6) join A to D' and cut at BC at D
∠ADB is 90° (∠BAD'=60° and ∠ABC=30°)

Answer 2

Answer:

GIVEN AB=AC THEREFORE  ∠B = ∠C AND ∠A =120° GIVEN SO ∠B+∠C =180-120 ANGLE SUM PROPERTY. = 60° THUS  EACH ANGLE = 30 = 60/2

Step-by-step explanation:

DRAW AB= 4.9CM

CONSTRUCT 120° AT ∠A

MARK 4.9CM MARK ON THE ANGLE AND MARK C

CONSTRUCT 30° ANGLE AT C THIS IF EXTENDED MUST JOIN B AT 30°

THUS TRIANGLE IS READY

PERPENDICULAR BISECTOR OF BC WILL ALSO JOIN WITH A

DIAGRAM