Construct ∆LMN in which base MN = 7cm, ∠LMN = 40° and LM-LN=3cm.
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1. Draw MN=5 cm.
2. Construct ∠M=75° and produce it to Y.
3. Cut off line segment MO=9 cm on MY.
4. Join N−O.
5. Draw a perpendicular bisector of NO such that it intersects MY at L.
6. Join L−N.
7. LMN is the required triangle.
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