Construct ∆ Lmn , such that LM = 6.2 cm , MN = 4.9 cm , LN = 5.6 cm.
Answers
Answered by
8
Step-by-step explanation:
- Take base of the triangle LM as 6.2cm.
- Take M as centre and radius of 5.6 cm and draw an arc.
- Now take L as center and radius of 4.9 cm bike cutting the the previous arc .
- let the intersection point made by two arcs be N.
- Now, join NL and NM.
- ∆LMN is the required triangle.
Hope you are satisfied with my answer....
so please mark me as brainlist and rate my answer....thank you
Attachments:
Answered by
2
Given:
LM = 6.2 cm
MN = 4.9 cm
LN = 5.6 cm
To find:
Construct ∆ LMN
Construction:
- Step 1: Draw a line segment LM of length 6.2 cm with help of a ruler.
- Step 2: Take a compass and measure 4.9cm on the ruler.
- Step 3: With M as center draw an arc of radius 4.9 cm above the line segment
- Step 4: Similarly, measure 5.6cm on the compass with a ruler and draw an arc with L as the center.
- Step 5: Mark the intersection point as N.
- Step 6: Join LN and MN.
Hence, ∆ LMN is constructed.
Similar questions