construct LNOP=110 protractor and bissect it
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Draw ∠BXA = 110° with the help of a protractor. Now, we use the following steps for required construction
1.Taking X as centre and any radius daw an arc to Intersect the rays XA and XB, say at E and D, respectively.
2.Taking D and E as centres and with the radius more than 1/2 DE, draw arcs to intersect
each other, say at F.
3.Draw the ray XF.
Thus, ray XF is the required bisector of the angle B X A. On measuring each angle, we get
∠BXC = ∠AXC = 55°.
[∴ ∠BXC = ∠AXC = 1/2 ∠BXA = 1/2 x 110° = 55° ].
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