construct parallelogram
AB=4cm
BC=6CM
ABC=60°
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Answered by
1
Step-by-step explanation:
constructruct a line AB of 4cm then on B make an angel of 60 degree and bc=6cm
Answered by
2
Answer:
it is a roughly figure
step by step explanation
⇒ Draw a line segment AB = 6cm.
⇒ Construct an angle of 60
∘
at point B.
⇒ Cut off BC = 4cm.
⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120
∘
at point A and C which meet at point D.
⇒ Thus, ABCD is a required parallelogram.
⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )
⇒ Perimeter of parallelogram ABCD=2(a+b)
⇒ 2(6+4) [From( 1 )]
∴ Perimeter of parallelogram ABCD=20cm.
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