Question

construct ∆ PQR ,given PQ=7.5 CM , triangle P=45°, triangle Q=90°

Answer 1

step 1 draw a right triangle with side named P Q R mark 7.5 on the line which have point P and Q
make an angle inside the triangle marking 45°
on P and 90° able on Q

Answer 2

Steps of construction:-
Step1: Draw a ine PQ of length 7.5cm.
Step2: Construct angle P=45° and extend it to X.
Step3: Construct angle Q=90°and extend it to Y.
Step4: Name the Point of intersection of Xand Y as R.