Construct ∆ PQR if it is given that PQ= 6cm , ∠RPQ = 300 and ∠ PQR = 1000
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Answer:
EXAMPLE SUM
Step-by-step explanation:
Steps of Construction :
(1) Draw a line PQ = 6 cm.
(2) Using compass taking P as centre draw an angle ∠P = 60°.
(3) Using compass taking Q as a centre draw an angle ∠Q = 30°.
(4) PS and QT intersect each other R.
(5) ∆ RPQ is the required triangle.
On measuring; ∠R = 90°, length of PR = 3 cm.
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