Math, asked by chauhanji93, 3 months ago

Construct ∆ PQR if it is given that PQ= 6cm , ∠RPQ = 300 and ∠ PQR = 1000

.​

Answers

Answered by SejaTalia26
0

Answer:

EXAMPLE SUM

Step-by-step explanation:

Steps of Construction :

(1) Draw a line PQ = 6 cm.

(2) Using compass taking P as centre draw an angle ∠P = 60°.

(3) Using compass taking Q as a centre draw an angle ∠Q = 30°.

(4) PS and QT intersect each other R.

(5) ∆ RPQ is the required triangle.

On measuring; ∠R = 90°, length of PR = 3 cm.

Similar questions