Construct ∆PQR if PQ = 5 cm , angle PQR = 75° and m angle QPR = 45°
In copy or in board please.
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Given that, m∠PQR = 105° and m∠QRP = 40°
∠PQR + ∠QRP + ∠RPQ = 180°.
105° + 40° + ∠RPQ = 180°
So, ∠RPQ = 35°
Now, let’s construct ΔPQR such that PQ = 5cm, ∠PQR = 105° and ∠RPQ = 35°, with the steps given
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