Math, asked by shrikantpatole173, 5 days ago

Construct ∆ PQR, in which angle Q = 70° , angle R = 80° and PQ+QR+PR = 9.5 cm​

Answers

Answered by harshchhawal233
3

Answer:

SSC (English Medium) 9th Standard

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Diagram

Construct Δ PQR, in which ∠Q = 70°, ∠R = 80° and PQ + QR + PR = 9.5 cm.

SOLUTION

Steps of construction:

(1) Draw seg AB of 9.5 cm length.

(2) Draw a ray making angle of 35° at point A.

(3) Draw another ray making an angle of 40° at point B.

(4) Name the point of intersection of the two rays as P.

(5) Draw the perpendicular bisector of seg AP and seg BP.

Name the points as Q and R respectively where the perpendicular bisectors intersect line AB.

(6) Draw seg PQ and seg PR.

Therefore, △PQR is the required triangle.

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