Question

Construct ΔPQR in which PQ= 5.5 cm, QR= 5 cm and PR= 7cm.​

Answer 1

∆pqr PQ= 5.5 cm, QR= 5 cm and PR= 7cm.

Answer 2

$\sf{Steps \: of \: Construction:}$

$\sf{ (i) Draw \: a \: line \: segment \: which \: is \: sufficiently \: long}$

$\sf{using \: ruler.}$

$\sf{(ii) Locate \: points \: P \: and \: Q \: on \: it \: such \: that}$

$\sf{PQ=5.4cm}$

$\sf{(iii) At Q, \: construct \: a \: line \: segment \: QS, \: sufficiently}$

$\sf{ large, such \: that \: ∠PQR=55˚ ; use \: protractor \: to}$

$\sf{ measure \: 55˚}$

$\sf{(iv) With \: Q \: as \: centre \: and \: radius \: 5.5cm, \: draw \: the}$

$\sf{ line \: cutting \: QS \: at \: R; \: join \: PR.}$

$\sf \red{Thus \: PQR \: is \: the \: required \: triangle.}$