Construct ΔPQR, in which PQ−PR=2.4cm,QR=6.4cm and ∠PQR=55
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Step-by-step explanation:
Steps of construction:
(1) Draw seg QR of length 6.4cm.
(2) Draw ray QA such that ∠RQA=55°
(3) Take point B on ray QA such that QB=2.4cm.
(4) Construct the perpendicular bisector of seg BR.
(5) Name the point of intersection of ray QA and the perpendicular bisector of seg BR as P.d
(6) Draw seg PR.
Therefore, ΔPQR is required triangle.
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