Math, asked by rakhishahu2808, 5 months ago

Construct ∆PQR in which QR=4.2cm LQ=40° and PQ+PR=8.5cm

Answers

Answered by 14singhbabita

1

Answer:

Draw as shown in the diagram

Hope the answer helps you.

Thank you!

Step-by-step explanation:

Steps to Construct

1) Draw segment QR of length 4.2 cm

2) Draw ray QT, such that angle RQT= 40°

3) Mark point S on ray QT, such that QS= 8.5cm

4) Join point R & S

5) Draw perpendicular bisector of segment RS intersecting ray QQT. Name the point as P

6) Join the points P & R.

Therefore, Angle PQR is the required triangle.

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