Question

Construct ∆PQR in which QR = 8cm and angle Q= 45° and PQ - PR = 1.5 cm ?
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Answer 1

Answer:

I don't know ask with other

Answer 2

Answer:

We have to draw a triangle PQR such that QR = 3cm, ∠ PQR = 45° and QP – PR = 2 cm

Steps of construction:

1. Draw a ray OX and cut off a line segment QR = 3 cm.

2. AT Q, construction ∠YQR = 45o.

3. From QY, cut off QS = 2 cm.

4. Join RS.

5. Draw perpendicular bisector of RS to Meet QY at P.

6. Join PR. Then PQR is the required triangle.