Question

ConstructΔPQR,inwhich Q=70°, R=80°andPQ+QR+PR=9.5cm.

Answer 1

1: Draw a line segment AB (PQ+QR+PR=9.5 cm ) = 9.5cm.

2: Draw an angle of 70° at A and an angle of 80° at B.

3: Bisect ∠A and ∠B. Let the bisectors of ∠A and ∠B intersect in P.

4: Draw perpendicular bisector DE of AP which intersect AB in Q and FG of AB which intersect AB in R.

5: Join PQ and PR.

∴ ΔPQR is the required triangle.

Answer 2

Answer:

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Step-by-step explanation:

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