Construct ΔPQR, PQ = 5.4 cm angle Q = 60 degree PR - PQ = 2.3 cm
SUPER URGENT NEED STEPS AND DIAGRAM!!!!
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Answered by
30
pr - pq = 2.3cm
pr = 7.7 cm
draw a line segment pq = 5.4 cm.
from q draw a 60 degree angle.mark it aq
now from p draw an arc with the radius 7.7 cm to cut aq and name it p.
therefore , pqr is the required triangle.
Yasmin:
ok and centre for 60 deg?
Answered by
12
Given:
- PQ = 5.4 cm
- ∠Q = 60°
- PR - PQ = 2.3 cm
To Find:
- To construct a triangle using the given data.
Solution:
- Steps involved for constructing a triangle are:
- Draw a line with 5.4 cm and consider it to be the base with PQ as the name. (Using a scale).
- Draw an angle of 60° from a point Q of the base. (Using a protractor) and name it QX.
- Using a compass cut an arc from the point Q towards the opposite side since PR - PQ = 2.3 cm is negative.
- You get a point, join the point with P.
- To get the triangle we draw a perpendicular bisector that should intersect PO.
∴ We get a triangle PQR.
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