Question

Construct ∆ PQR such that angle P = 45° , PQ= 4.5 cm and PR – RQ=2.6 cm​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Draw a line segment QR = 5 cm.

(b) Taking Q as centre and radius 4.5cm, draw an arc.

(c) Similarly, taking R as centre and radius 4.5 cm,

draw another arc which intersects first arc at P.

(d) Join PQ and PR.

It is the required isosceles Δ PQR