Question

Construct ∆PQR such that angle R=100%,QR=RP=5.4 cm

Answer 1

Answer:

In ∆PQR,

R = 100° ,QR=RP=5.4cm.

Therefore, this is an isosceles triangle,

1) First draw seg QR

2) Then keep the protractor on point R.

3) Measure 100° from R.

4) Draw RP.

5) Join QP

∆ is constructed.

Answer 2

Answer:

first draw a line segment of 5.4 cm name QR

then on Q draw 100°

and measure 5.4 cm on compass and make an arc using the compass of measure 5.4 cm on Q of 100° ,name P

now join PR

∆PQR is the required triangle