Construct ∆PQR such that measure of angle P=60°, measure of angle R=120°,PQ=5cm
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Step-by-step explanation:
(i) Steps of Construction:
(i) Draw a line segment PQ = 6 cm.
(ii) At P, draw a ray making an angle of 45°
(iii) At Q, draw another ray making an angle of 60° which intersects the first ray at R.
∆ PQR is the required triangle.
On measuring ∠R, it is 75°.
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