Question

Construct ΔPQR such that ∠P=70°, ∠R=50°, QR=7.3 cm. and construct its circumcircle.

Answer 1

Answer:

Step-by-step explanation:

∠P=70°  ∠R=50°

=> ∠Q = 180° - 70° - 50° = 60°

Step 1 : Draw QR = 7.3 cm using Ruler

Step 2 Draw ∠Q = 60° using protector

Step 3 Draw ∠R = 50° using protector

Step 4 JOin intersection point of Angles P with Q & R

ΔPQR is constructed

Step 5  Draw perpendicular bisector of PQ

Step 6 Draw perpendicular bidector of QR

: intersection point of Perperpendicular bisector is center of circum circle

Step 7 : from intersection using compass take length upto P and draw circle

Circumcircle is constructed

Answer 2

Answer:

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