Question

Construct ∆ PQR, such that perimeter of ∆ PQR is 16cm and angle Q = 90° and QR = 5cm.​

Answer 1

Steps of Construction:

1. Draw a line segment QR=5 cm.

2. At Q, construct an angle of 90

∘

.

3. Cut an arc QD of 11 cm(16−5=11).

4. Draw perpendicular bisector of DR which intersects QD at P.

5. Join P−R. Then, PQR is the required triangle

rough diagram h construction ka step dhek ke bana sakte ho

hope it will help u