Math, asked by shariyababy, 3 months ago

construct Δ PQR such that QR=5cm,∠Q=105° and ∠R=40°​

Answers

Answered by sohelasu934
12

Answer:

Draw PQ of 5cm

make angle Q of 105° (bisect 90° & 120°)

use angle sum property to find angle P

you will find that angle P is 35°

draw angle P of 35°

mark the point of intersection as R

Step-by-step explanation:

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