Question

Construct ΔPQR, such that QR=6.5 cm, ∠PQR=60° and PQ-PR=2.5 cm.​

Answer 1

Step-by-step explanation:

i. Draw seg QR of length 6.5 cm.

ii. Draw ray QT, such that ∠RQT = 600.

iii. Mark point S on ray QT such that l(QS) = 2.5 cm.

iv. Join points S and R.

v. Draw perpendicular bisector of seg SR intersecting ray QT. Name the point as P.

vi. Join the points P and R. Hence, ∆PQR is the required triangle