Question

Construct ∆ PQR such that QR=6cm, angle Q= angle R=60°. Measure the other two sides of triangle and name the triangle ​

Answer 1

Answer:

We have given QR=6cm

∠Q=∠R=60

The third angle of ΔPQR:-

∠P+∠Q+∠R=180

o

∠P+60

o

+60

o

=180

o

∠P+120

o

=180

o

∠P=60

o

All the angles of ΔPQR is equal i.e., each angle is 60

o

.

So, the corresponding sides will also be equal

i.e., PQ=QR=PR=6cm

All the sides and angles are equal of ΔPQR, so it is known as equilateral triangle.

Step-by-step explanation:

Hope it helps

Please mark as brainlist

Answer 2

Answer:

We have given QR=6cm

$∠Q=∠R=60$

The third angle of ΔPQR:-

$∠P+∠Q+∠R=180$

$∠P+60 </p><p></p><p> +60 </p><p></p><p> =180 </p><p>$

∠P=60°

All the angles of ΔPQR is equal i.e., each angle is 60°.

So, the corresponding sides will also be equal

i.e., PQ=QR=PR=6cm

All the sides and angles are equal of ΔPQR, so it is known as equilateral triangle.