Question

Construct ∆PQR where base QR = 4.1 cm, ∠Q = 60° and PQ + PR = 8.5 cm

Answer 1

Method:

1). Draw base QR = 4.1 cm

2). using compass or protractor, draw an angle of 60° w.r.t. QR at point Q.. draw a line say QS on that angle.

3) Cut line segment of 8.5 cm on QS

4). join S and R

5) using compass, draw perpendicular bisector of side SR

6) mark the intersection point of perpendicular bisector of SR and SQ as P

7) join PQ and PR

8) ∆ PQR is the desired ∆