Question

Construct ∆PQR where PQ=5.5 cm QR=7cm and AngleQ=75°​

Answer 1

Answer:

Solution:

Draw a line PQ = 6 cm

Using compass taking P as center draw an angle P = 60°

Using compass taking Q as center draw an angle Q = 30°

PS and QT intersect each other R.

RPQ is the required triangle.

On measuring R = 90, length of PR = 3 cm.