Construct Δ PQR with QR = 5.5 cm, PQ + PR = 11 cm and ∠ Q=60°
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Construct a triangle PQR in which QR = 6 cm, Q = ∠60° and PR - PQ = 2 cm. i) Draw a line QR = 6 cm. Make an angle of 60° at a point RQX using a protractor and extend it below line QR. ii) With Q as center and radius as 2 cm, draw an arc to intersect the ray QX at Z.
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