Question

construct quadratic equation using the roots 7 and -3​

Answer 1

Step-by-step explanation:

Given the roots are 7 and -3

We can solve this in two ways

Method 1

x = 7 and x = -3

then, (x - 7) and (x + 3) must be the factor of the Quadratic equation we are constructing,

then,

p(x) = (x - 7)(x + 3)

p(x) = x² + 3x - 7x - 21

p(x) = x² - 4x - 21

Method 2

x = 7(Alpha) and x = -3(B

We know,

Sum of zeroes = -b/a

7 + (-3) = -b/a

4 = -b/a

b/a = -4

also, Product of zeroes = c/a

7 × -3 = c/a

-21 = c/a

Let the Quadratic equation be,

x² + (b/a)x + (c/a) = 0

x² + (-4)x + (-21) = 0

x² - 4x - 21 = 0

Hope it helped and you understood it........All the best