Question

construct rectangle MUST such that I(MU)=5.2cm,I(UT)=6.9cm. std 8th
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Answer 1

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we know that,

♡ Each angles of a rectangle are equal to 90°.

so, in right angled ATMU right angle at M,

→ TM²+ MU²=UT² (By pythagoras theorem)

→TM² + 5.2² 6.9²

→TM² = 6.9² - 5.2² ->

→TM² (6.9+ 5.2)(6.9 - 5.2)

→ TM² = 12.1 1.7

→ TM² = 20.57

→ TM = √(20.57)

→ TM = 4.54 cm.

Now, steps of construction :

■ Draw a line segment TS of 5.2 cm.

■ Draw line segment MT perpendicular to TS at T and US perpendicular to TS at S. • Measure MT and US of length 4.54 with the help of scale.

■ Join MU.

■ MUST is required rectangle.

• Please Drop Some Thanks.

Answer 2

Step-by-step explanation:

so, in right angled ATMU right angle at M,

→ TM²+ MU²=UT² (By pythagoras theorem)

→TM² + 5.2² 6.9²

→TM² = 6.9² - 5.2² ->

→TM² (6.9+ 5.2)(6.9 - 5.2)

→ TM² = 12.1 1.7

→ TM² = 20.57

→ TM = √(20.57)

→ TM = 4.54 cm.

Now, steps of construction :

■ Draw a line segment TS of 5.2 cm.

■ Draw line segment MT perpendicular to TS at T and US perpendicular to TS at S. • Measure MT and US of length 4.54 with the help of scale.

ANSWER

■ Join MU.