Construct rectangle MUST such that I(MU)=5.2cm, (UT)=6.9cm.
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Given :- Construct rectangle MUST such that I(MU)=5.2cm, (UT)=6.9cm.
Answer :-
we know that,
- Each angles of a rectangle are equal to 90° .
so, in right angled ∆TMU right angle at M ,
→ TM² + MU² = UT² (By pythagoras theorem)
→ TM² + 5.2² = 6.9²
→ TM² = 6.9² - 5.2²
→ TM² = (6.9 + 5.2)(6.9 - 5.2)
→ TM² = 12.1 * 1.7
→ TM² = 20.57
→ TM = √(20.57)
→ TM = 4.54 cm .
now, steps of construction :-
- Draw a line segment TS of 5.2 cm .
- Draw line segment MT perpendicular to TS at T and US perpendicular to TS at S .
- Measure MT and US of length 4.54 with the help of scale .
- Join MU .
- MUST is required rectangle.
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