Question

construct rombus : park,pr=9cm and <p=70°


note:

draw and construct with correct measures ​

Answer 1

$PARK$ is the required Rhombus.

Step-by-step explanation:

Given,

construct rhombus  $PARK$ where diagonal $PR=9\ cm\ and\ \angle P=70\ degree$

Following steps:

• Draw a perpendicular angle such that $\angle XOY=90\ degree$ using protector.
• Extend the line $XO\ and\ YO$ such that $XM\ and\ YN$

• $O$ as center and $4.5\ cm$$(\frac{9}{2}=4.5)$ as radius draw two arc on line $OX\ and\ OM$ at $R\ and P$

• Similarly, $O$ as center and $4.5\ cm$$(\frac{9}{2}=4.5)$ as radius draw two arc on line $OY\ and\ ON$ at $A\ and\ K$

• Join $PA,AR,RK\ and\ PK$

Hence, $PARK$ is the required Rhombus.

Answer 2

Rhombus is constructed  , park,pr=9cm and <p=70°

Step-by-step explanation:

Step 1 : Draw a line Segment PR = 9 cm

Step 2 : Draw perpendicular biscetor of PR

( Using compass , Darw arc on both sides taking p as center and then keeping same width draw arcs taking r as center such that it intersects arcs at x & y, Draw a line passing through x , y intersecting pr at O

Step 3 : Draw an angle of 35° at p on both sides on rp , inetersecting perpendicular bisector of pr at a and k

Step 4 : join ar & kr

Rhombus is constructed

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