Construct square ABCD: which has diagonal 6 cm
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Heyy mate❤✌✌❤
Here's your Answer....
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Diagonal = 6cm.
By pythagoras Theorem,
BD^2 = AD^2 + AB^2.
=> 6^2 = X^2 + X^2
=> 36 = 2X^2
=> X^2 = 18
=> X = 3 ROOT 2.
So, A Side of square = 3 root 2.
✔✔✔✔
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Diagonal = 6cm.
By pythagoras Theorem,
BD^2 = AD^2 + AB^2.
=> 6^2 = X^2 + X^2
=> 36 = 2X^2
=> X^2 = 18
=> X = 3 ROOT 2.
So, A Side of square = 3 root 2.
✔✔✔✔
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Answered by
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hope this helps..........
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