Question

construct tha squarePQR such that PQ=5cm, PR=6CM and { 60°, and locate its centroid with diagram​

Answer 1

Step-by-step explanation:

Hi,

I can help you with the steps needed to answer the question.

1) Draw a straight line PQ = 5cm

2) Located angle 60 (Using a circular or a protractor), Now, Angle QPR = 60

3) Let PR = 6cm

4) Join R and Q

Locating the centroid:

1) Locate the centre of each of the sides of the triangle PQ, QR, RP.

2) Name the centres of the sides PQ, QR, RP as A, B, C respectively.

3) Join PB, QC, RA.

4) The point that PB, QC, RA meet is the centroid of the triangle.

Hope it helps !!