Math, asked by chachigaonkar193, 1 day ago

construct the ∆ABC, angle B=60°, angle C=90°; AB+BC+CA=11.9 (with full Explaination)​

Answers

Answered by XxitzKing02xX
5

\large\mathscr\color{black}\colorbox{red}{\colorbox{orange}{\colorbox{yellow}{\colorbox{green}{\colorbox{blue}{\colorbox{indigo}{\colorbox{violet}{\underline {ANSWER}}}}}}}}

Given  :  AB+BC+CA=11 cm   ,  ∠B = 60° & ∠C = 45°  

To Find :   Construct triangle

Solution:

Step 1 : Draw  a line segment XY  = 11 cm

Step 2 : Make an angle of 60 ° at X on XY using protector

Step 3 : Make an angle of 45° at Y on XY using protector

Step 4 : Draw angle bisector of 60°  & 45° and let them intersect at A

Step 5 : Draw perpendicular bisector of AX  & AY and let them intersect XY at B  & C

ΔABC is required triangle

∠B = 60° & ∠C = 45° and AB+BC+CA = 11 cm

 \\ \\ \bf\bold{\mathtt\pink{Answer \: By:-}} \huge{\mathcal\red{XxItzKing02xX}}

Similar questions