Question

construct the ∆abcif it is given that bc is 6cm m<abc is 30° and angle BCA is100°​

Answer 1

Answer:

Step 1 : Draw a line segment BC of length 7cm

Step 2 : Draw an angle of 45

o

from point B

Step 3 : From Ray AX cut off the line segment BD=1cm

Step 4 : Join C to D

Step 5 : Draw side bisector of DC

Step 6 : Extend side bisector of DC it intersect the Ray BX at point A

Step 7 : Join A to C, ABC is the required triangle.

On measuring, AB=6.1cm,AC=5.1cm

Answer 2

Answer

Steps:

1. Draw a line AB of length 6 cm.

2. Make an angle of 30

∘

at A and extend the line from A making this angle.

3. Make an angle of 60

∘

at B and extend the line from B making this angle till it meets the line from step 2 at point C.

Hence, we got the △ABC

Now,

4. Extend the line AB to B

′

, such that AB

′

=8 cm.

5. Make an angle of 60

∘

at B

′

and extend the line from B

′

making this angle till it meets the line from step 2 at point C

′

.

Hence, we got the △AB ′ C ′