Question

Construct the centroid of tringle PQR whose sides are PQ=8cm ; QR=6cm; RP =7cm.?

Answer 1

Answer:

i not understante this guestion

Answer 2

Answer:

The sides of ΔPQRPQR are PQ=8cmPQ=8cm ,QR=6cmQR=6cm and RP=7cmRP=7cm .

To find:

We have to find the centroid of the ΔPQRPQR by constructing it.

Solution:

Firstly, take the side PQPQ to be the base. (You can take any side to be the base as per your wish.)

Now, from the point QQ draw an arc of length 6cm6cm .

Then draw an arc of length 7cm7cm keeping the compass on point PP .

The point where these two arcs meet is point RR . Then, Join point RR with points PP and QQ .

A triangle with vertices PP , QQ and RR with sides PQ=8cm , QR=6cm , and RP=7cm will be constructed.

Now construct a perpendicular bisector for all the sides.

The point inside the triangle where all these bisectors meet each other is known as the centroid of the triangle. Label it as Centroid.