Question

Construct the parallelogram PQRS in which PQ = 9 cm, QR = 6 cm and PQR = 115° (Q is an angle here) . Measure and write down the length of PR.
On the same diagram, construct (i) the locus of a point X which moves so that it is equidistant from PQ and RQ,
(ii) the locus of a point Y which moves so that QYS = 90°. (Y is an angle here)
The position of a point Z, which lies inside the parallelogram, is such that QZS ≤ 90° (Z is an angle here) and Z is nearer to PQ than to RQ. Indicate clearly by shading, the region in which the point Z must lie.​

Answer 1

Answer:

Draw a line segment PR=7 cm.

With 4 cm as radius, draw an arc from P.

Similarly, with radius as 6 cm from R, cut the arc just drawn.

They will intersect at Q. Join PQ and QR.

With 5. 5 cm as radius, draw an arc from P. ...

They will intersect at S. Join PS and RS.

PQRS is the required quadrilateral.

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