construct the parallelogram PQRS with PQ=4.5cm,QR=3cm,and angle PQR=60 degrees?
Answers
Answered by
237
"1. Draw a line segment PQ = 4.5 cm
2. Take a compass and keeping Q as a centre construct an angle of 60 degrees.
3. Now take the radius of 3 cm, draw an arc on the 60-degree angle line. The intersection point of the 3 cm arc and 6 degrees will be R.
4. As per the supplementary property of a parallelogram, SPQ + PQR = 180. Hence draw an angle of 120 degrees on point P.
5. Now draw an arc of 3 cm and mark it as S
6. Join PQRS to form a parallelogram.
"
Answered by
116
Answer:
please follow me
mark me brainlists answer
Attachments:
Similar questions