Question

Construct the PQR such that
PQ=6-7cm, Q R = 5.8cm
PR = 6-9 ch. Construct it's
incircle​

Answer 1

Step-by-step explanation:

Let the centre of the circle be O.

AB = 12 cm

OC = 12 cm

OC ⊥ AB

We know perpendicular drawn from the centre of the circle to the chord, bisects the chord.

So, AC = 6 cm

In ⃤ OCA,

OC2+AC2=AO2⇒82+62=AO2⇒AO2=100⇒AO=10

Thus, AO = 10 cm

Diameter = 2 × 10 cm = 20 cm.