Question

construct the quadratic equation whose roots are √3 and 3√3​

Answer 1

Answer:

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Step-by-step explanation:

$so \: here \: given \: roots \: of \: particular \: quadratic \: equation \: are \: \sqrt{3} \: and \: 3 \sqrt{3}$

$so \: let \: \alpha \: be \: \sqrt{3} \: and \: \beta \: be \: 3 \sqrt{3}$

$thus \: then \: \\ \alpha + \beta = \sqrt{3} + 3 \sqrt{3} \\ also \: \alpha \beta = \sqrt{3} \times 3 \sqrt{3} \\ = 3 \times 3 \\ = 6$

$so \: now \: applying \\ x \: square -( \alpha + \beta )x + \alpha \beta = 0$

thus we get now

=x square-3 root 3x+6=0

hence our required quadratic equation is

x square-3 root 3x+6=0